Find max and second max salary for a employee table MySQL

Question

Suppose that you are given the following simple database table called Employee that has 2 columns named Employee ID and Salary:

  Employee
  Employee ID    Salary
   3            200
   4            800
   7            450

I wish to write a query select max(salary) as max_salary, 2nd_max_salary from employee

then it should return

  max_salary   2nd_max_salary
   800             450

i know how to find 2nd highest salary

   SELECT MAX(Salary) FROM Employee
  WHERE Salary NOT IN (SELECT MAX(Salary) FROM Employee )

or to find the nth

  SELECT FROM Employee Emp1 WHERE (N-1) = ( SELECT COUNT(DISTINCT(Emp2.Salary)) FROM Employee Emp2
  WHERE Emp2.Salary > Emp1.Salary)

but i am unable to figureout how to join these 2 results for the desired result

 

Answer 1

SELECT MAX(SALARY) FROM Employee WHERE SALARY < (SELECT MAX(SALARY) FROM Employee); This query will give you the desired output i.e 12000, which is the second highest salary.