How to convert INT to STRING in Solidity

+1 vote

Following is my code :

pragma solidity ^0.4.4;

contract someContract {

    uint i;

    function test() pure returns (string) {

      return "Here and Now is Happiness!";

    }

    function love() pure returns(string) {

        i = i +1;

        return "I love " + functionname(i) + " persons" ;
    }



}

Is there a way I can convert my int to string? If so, what is the functionname?

Jun 27, 2018 in Blockchain by sabby
• 4,390 points
12,384 views

2 answers to this question.

+1 vote
Best answer

Look at the following code :

function uintToString(uint v) constant returns (string str) {
        uint maxlength = 100;
        bytes memory reversed = new bytes(maxlength);
        uint i = 0;
        while (v != 0) {
            uint remainder = v % 10;
            v = v / 10;
            reversed[i++] = byte(48 + remainder);
        }
        bytes memory s = new bytes(i + 1);
        for (uint j = 0; j <= i; j++) {
            s[j] = reversed[i - j];
        }
        str = string(s);
    }

This should help.

You can also go through these posts:

https://ethereum.stackexchange.com/questions/10811/solidity-concatenate-uint-into-a-string

https://ethereum.stackexchange.com/questions/10932/how-to-convert-string-to-int

answered Jun 27, 2018 by Christine
• 15,790 points

selected Apr 30, 2019 by Omkar
Works well. But takes time. I don't know why the delay.
Hi @Roshni. I tried this code but I didn't face any delay. Maybe it's because of your system. But yes, this code works fine without any delay.
+1 vote
function uint2str(uint i) internal pure returns (string){
    if (i == 0) return "0";
    uint j = i;
    uint length;
    while (j != 0){
        length++;
        j /= 10;
    }
    bytes memory bstr = new bytes(length);
    uint k = length - 1;
    while (i != 0){
        bstr[k--] = byte(48 + i % 10);
        i /= 10;
    }
    return string(bstr);
}
answered Aug 27, 2018 by Barkha

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