How to print first character of each word in upper case of a string in Python

Question

Lets say there is a string such as "this is a sample python program". 

How to write a program such that it would print the first character of each word in the string. such as T,I,A,S,P,P

i.e. This Is A Sample Python Program ?

Answer 1

You can use split() using space as delimiter to fetch each word and then use counter-chindex to find if it is first character of each word. If yes, then apply upper()

Below is the sample code:

s1="this is a sample python program"
s1.split(" ")
chindex=1
for letter in s1.split(" "):
     if chindex==1:
         print(letter[0].upper()+""+letter[1:len(letter)], end=" ")
     else:
         print(letter)

Comments

how about..?

"hello     edurekha"

how to make this.."

---

Hey, 

You can try this:

Use .join():

print(" ".join([item1, item2]))

The default for print, however, is to put a space between arguments, so you could also do:

print(item1, item2)

I hope this will be helpful.

---

s1="this is a sample python program"
s1.split(" ")
for letter in s1.split(" ")

           print(letter[0].upper()+""+letter[1:len(letter)], end=" ")

This should work as though

Answer 2

class Solution:

    def firstAlphabet(self, s):

            self.s=s

             k=''

             k=k+s[0]

             for i in range(len(s)):

                    if s[i].isalpha():

                           pass

                    else:

                            k=k+s[i+1]

               return k