heapify returns NoneType

0 votes

I have the following code:

b = heapify([5,4,9,1])

and when I check for the following

type(b)

It shows it's NoneType instead of list type. How do I fix this issue?

Jul 26, 2019 in Python by ana1504.k
• 7,890 points
109 views

1 answer to this question.

0 votes

The heapify() method transforms the list in-place. This means that it alters the list, but does not return the modified list. As agf mentions below, heapify() returns None to protect you from this mistake. Therefore, if you do

lst = [5,4,9,1]
heapify(lst)
type(lst)

you will see that lst is now heapified.

answered Jul 26, 2019 by SDeb
• 13,250 points

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