Print the line if it contains a specific string by using groovy.

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I am having a Jenkins log file and I am trying to print those lines which are having string "FOUND" in it.

How do I write the code for it in Groovy as I am new to it? Can anyone help me with this?

Thanks.

Apr 27, 2018 in Jenkins by Atul
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0 votes

You can try the code written below:

def lines = new File('/tmp/test123.txt').readLines()
def result = lines.findAll { it.contains('FOUND') }
println result*.toString()

I hope that it will resolve your query. 
answered Apr 27, 2018 by shubham
• 6,480 points

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