How can I replace the nth occurence using regex in VBA

0 votes

I attempted to substitute "hello" for the second occurrence of a number in the phrase "This 9 is 8 a 77 6 test." I, therefore, desired the outcome to read "This 9 is hello a 77 6 test."
I'm receiving "hellohello test" instead.

I'm using:

=RegexReplace("This 9 is 8 a 77 6 test","(?:\D*(\d+)){2}","hello")

where RegexReplace is defined below.:

Function RegexReplace(text As String, pattern As String, replace As String)

        Static re As Object

        If re Is Nothing Then
            Set re = CreateObject("VBScript.RegExp")
            re.Global = True
            re.MultiLine = True
        End If

        re.IgnoreCase = True
        re.pattern = pattern
        RegexReplace = re.replace(text, replace)
        Set re = Nothing

End Function
Jan 13, 2023 in Others by Kithuzzz
• 38,000 points
1,207 views

1 answer to this question.

0 votes

Use:

=RegexReplace("This 9 is 8 a 77 6 test","^(\D*\d+\D+)\d+","$1hello")

See the regex demo.

Details:

  • ^ - start of string
  • (\D*\d+\D+) - Group 1: zero or more non-digits + one or more digits + one or more non-digits (this value will be restored in the result using the numbered replacement backreference $1)
  • \d+ - one or more digits.
answered Jan 13, 2023 by narikkadan
• 63,600 points

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