Is there any way to remove NA values from a vector?

If we have a vector consisting of lot values with NA values, how to remove it?

Suppose I have to sum the vector without including NA values?
Apr 23, 2018 193,824 views

To calculate sum we can use "sum()" Func by passing argument "na.rm=TRUE"

```x<-c(1,23,45,NA,155,78,NA)

sum(x,na.rm=TRUE)```

Want to remove NA from the vector

`x<-x[!is.na(x)]`

• 1,720 points
`data = data[!is.na(data)]\`
answered Apr 5, 2019 by anonymous
Yup!! Very accurate to remove NA values.

using the function "complete.cases"

for example, if you want to remove the NA in dataset ,

> x <- c(1, 2, NA, 4, NA, 5)
> y <- c("a", "b", NA, "d", NA, "f")
> good <- complete.cases(x, y)
> good
[1] TRUE TRUE FALSE TRUE FALSE TRUE
> x[good]
[1] 1 2 4 5
> y[good]
[1] "a" "b" "d" "f"

above is from coursera lecture R from Professor Peng

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answered Jun 18, 2019 by anonymous
That's a nice way to go about it. It's an unusual approach but got the same expected output. Thanks

When you view y1,y2, they would be shown as below.

It would show you rows with indices and those with nulls.

answered Aug 1, 2019 by anonymous
• 33,030 points

Hello team,

you can use na.omit

```x <- c(NA, 3, NA, 5)
na.omit(x)
[1] 3 5
attr(,"na.action")
[1] 1 3
attr(,"class")
[1] "omit"```
answered Dec 9, 2020 by anonymous
• 82,880 points

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