How to generate addresses from a file rather than specific phase

0 votes

I am using the following python script to generate bitcoin wallet address, however I am having to enter each phrase into the code and generate one at a time, how would I adjust the code to generate bitcoin addresses from a list.txt file held in the same directory. 

This is my code:

#!/usr/bin/env python
# Joric/bitcoin-dev, june 2012, public domain

import hashlib
import ctypes
import ctypes.util
import sys

ssl = ctypes.cdll.LoadLibrary (ctypes.util.find_library ('ssl') or 'libeay32')

def check_result (val, func, args):
    if val == 0: raise ValueError 
    else: return ctypes.c_void_p (val)

ssl.EC_KEY_new_by_curve_name.restype = ctypes.c_void_p
ssl.EC_KEY_new_by_curve_name.errcheck = check_result

class KEY:
    def __init__(self):
        NID_secp256k1 = 714
        self.k = ssl.EC_KEY_new_by_curve_name(NID_secp256k1)
        self.compressed = False

    def __del__(self):
        if ssl:
        self.k = None

    def generate(self, secret=None):
        if secret:
            self.prikey = secret
            priv_key = ssl.BN_bin2bn(secret, 32, ssl.BN_new())
            group = ssl.EC_KEY_get0_group(self.k)
            pub_key = ssl.EC_POINT_new(group)
            ctx = ssl.BN_CTX_new()
            ssl.EC_POINT_mul(group, pub_key, priv_key, None, None, ctx)
            ssl.EC_KEY_set_private_key(self.k, priv_key)
            ssl.EC_KEY_set_public_key(self.k, pub_key)
            return self.k
            return ssl.EC_KEY_generate_key(self.k)

    def get_pubkey(self):
        size = ssl.i2o_ECPublicKey(self.k, 0)
        mb = ctypes.create_string_buffer(size)
        ssl.i2o_ECPublicKey(self.k, ctypes.byref(ctypes.pointer(mb)))
        return mb.raw

    def get_secret(self):
        bn = ssl.EC_KEY_get0_private_key(self.k);
        bytes = (ssl.BN_num_bits(bn) + 7) / 8
        mb = ctypes.create_string_buffer(bytes)
        n = ssl.BN_bn2bin(bn, mb);
        return mb.raw.rjust(32, chr(0))

    def set_compressed(self, compressed):
        self.compressed = compressed
        if compressed:
            form = self.POINT_CONVERSION_COMPRESSED
        ssl.EC_KEY_set_conv_form(self.k, form)

def dhash(s):
    return hashlib.sha256(hashlib.sha256(s).digest()).digest()

def rhash(s):
    h1 ='ripemd160')
    return h1.digest()

b58_digits = '123456789ABCDEFGHJKLMNPQRSTUVWXYZabcdefghijkmnopqrstuvwxyz'

def base58_encode(n):
    l = []
    while n > 0:
        n, r = divmod(n, 58)
    return ''.join(l)

def base58_decode(s):
    n = 0
    for ch in s:
        n *= 58
        digit = b58_digits.index(ch)
        n += digit
    return n

def base58_encode_padded(s):
    res = base58_encode(int('0x' + s.encode('hex'), 16))
    pad = 0
    for c in s:
        if c == chr(0):
            pad += 1
    return b58_digits[0] * pad + res

def base58_decode_padded(s):
    pad = 0
    for c in s:
        if c == b58_digits[0]:
            pad += 1
    h = '%x' % base58_decode(s)
    if len(h) % 2:
        h = '0' + h
    res = h.decode('hex')
    return chr(0) * pad + res

def base58_check_encode(s, version=0):
    vs = chr(version) + s
    check = dhash(vs)[:4]
    return base58_encode_padded(vs + check)

def base58_check_decode(s, version=0):
    k = base58_decode_padded(s)
    v0, data, check0 = k[0], k[1:-4], k[-4:]
    check1 = dhash(v0 + data)[:4]
    if check0 != check1:
        raise BaseException('checksum error')
    if version != ord(v0):
        raise BaseException('version mismatch')
    return data

def gen_eckey(passphrase=None, secret=None, pkey=None, compressed=False, rounds=1, version=0):
    k = KEY()
    if passphrase:
        secret = passphrase.encode('utf8')
        for i in xrange(rounds):
            secret = hashlib.sha256(secret).digest()
    if pkey:
        secret = base58_check_decode(pkey, 128+version)
        compressed = len(secret) == 33
        secret = secret[0:32]
    return k

def get_addr(k,version=0):
    pubkey = k.get_pubkey()
    secret = k.get_secret()
    hash160 = rhash(pubkey)
    addr = base58_check_encode(hash160,version)
    payload = secret
    if k.compressed:
        payload = secret + chr(1)
    pkey = base58_check_encode(payload, 128+version)
    return addr, pkey

def reencode(pkey,version=0):
    payload = base58_check_decode(pkey,128+version)
    secret = payload[:-1]
    payload = secret + chr(1)
    pkey = base58_check_encode(payload, 128+version)
    print get_addr(gen_eckey(pkey))

def test(otherversion):
    # random compressed
    print get_addr(gen_eckey(compressed=True,version=otherversion),version=otherversion)

    # uncomment these to create addresses via a different method
    # random uncompressed
    #print get_addr(gen_eckey())
    # by secret
    #print get_addr(gen_eckey(secret=('%064x' % 0xdeadbabe).decode('hex')))
    # by passphrase
    #print get_addr(gen_eckey(passphrase='Satoshi Nakamoto'))
    # by private key
    #print get_addr(gen_eckey(pkey='5K1HkbYffstTZDuV4riUWMbAMkQh57b8798uoy9pXYUDYeUHe7F'))
    #print get_addr(gen_eckey(pkey='L3ATL5R9Exe1ubuAnHVgNgTKZEUKkDvWYAWkLUCyyvzzxRjtgyFe'))

    # uncomment this to reencode the private keys created by early versions of this script

if __name__ == '__main__':
    import optparse
    parser = optparse.OptionParser(usage="%prog [options]")
    parser.add_option("--otherversion", dest="otherversion", default=0,
                    help="Generate address with different version number")
    (options, args) = parser.parse_args()

Sep 7, 2018 in Blockchain by digger
• 27,620 points

1 answer to this question.

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
0 votes

If the file with the passwords is password.txt (you have to save one password per line) you can do:

#fileName = string
def parseFile(filename):
    with open(filename, 'r') as passwords:
        for password in passwords:
            var adds = newAddress(password); # you have to define newAddress
answered Sep 7, 2018 by MI3

Related Questions In Blockchain

0 votes
1 answer

How is a request sent from an app to a smart contract?

Yes, the contract is distributed by every node ...READ MORE

answered Jun 4, 2018 in Blockchain by Perry
• 16,450 points
0 votes
1 answer

How to retrieve data from a block to a blockchain?

web3.eth.getTransaction(txHash) will returns transaction details like blockHash, transactionIndex, ...READ MORE

answered Jun 26, 2018 in Blockchain by Perry
• 16,450 points
0 votes
1 answer
0 votes
1 answer

Protocols used in a distributed/dlt system for the nodes to establish communication

yes all are over TCP/IP connections secured by TLS encryption in hashgraph architecture-hashgraph, ...READ MORE

answered Aug 6, 2018 in Blockchain by ariaholic
• 7,320 points
0 votes
1 answer

Truffle tests not running after truffle init

This was a bug. They've fixed it. ...READ MORE

answered Sep 11, 2018 in Blockchain by Christine
• 15,790 points
0 votes
1 answer
+1 vote
2 answers

How to return value from a chaincode in Hyperledger Fabric?

Hyperledger Fabric supports only 2 types of ...READ MORE

answered Jun 13, 2018 in Blockchain by Perry
• 16,450 points

© 2018 Brain4ce Education Solutions Pvt. Ltd. All rights Reserved.
"PMP®","PMI®", "PMI-ACP®" and "PMBOK®" are registered marks of the Project Management Institute, Inc. MongoDB®, Mongo and the leaf logo are the registered trademarks of MongoDB, Inc.