How do I convert a String to an int in Java

0 votes
My String contains only numbers, and I want to return the number it represents.

For example, given the string "1234" the result should be the number 1234.

How can I convert a String to an int in Java?
Jul 28, 2020 in Java by kartik
• 37,510 points
2,566 views

2 answers to this question.

0 votes

Hello @kartik,

We can use the parseInt(String str) method of the Integer wrapper class for converting a String value to an integer value.

For example:

String strValue = "12345";
Integer intValue = Integer.parseInt(strVal);

The Integer class also provides the valueOf(String str) method:

String strValue = "12345";
Integer intValue = Integer.valueOf(strValue);

We can also use toInt(String strValue) of NumberUtils Utility Class for the conversion:

String strValue = "12345";
Integer intValue = NumberUtils.toInt(strValue);

Hope it helps!!

Become certified expert with Java certification here.

Thank you!

answered Jul 28, 2020 by Niroj
• 82,880 points

edited Jun 22, 2023 by Khan Sarfaraz
0 votes
Use the lines of code mentioned below:-

String myString = "1234"; 
int foo = Integer.parseInt(myString);

The documentation of Java mentions that the "catch" is when this function can throw a NumberFormatException, which you can handle by using the code mentioned below:
 

int foo; 
try { 
    foo = Integer.parseInt(myString); 
} 
catch (NumberFormatException e) { 
  foo = 0; 
}

This will ensure that they default a malformed number to 0, but you could try another way if wished upon. However, you can also use an Ints method from the Guava library, which is in combination with Java 8's Optional and hence, this makes a more powerful and concise way to convert a string into an int:
 

import com.google.common.primitives.Ints; 

int foo = Optional.ofNullable(myString) 
.map(Ints::tryParse) 
.orElse(0)
answered Feb 9, 2022 by Soham
• 9,700 points

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