showing an error in a MySQL trigger

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Sep 27, 2019 in Database by Daric
• 500 points
836 views

1 answer to this question.

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use this code:

CREATE TRIGGER sample_trigger_msg 
    BEFORE INSERT
FOR EACH ROW
    BEGIN
IF(NEW.important_value) < (1*2) THEN
    DECLARE dummy INT;
    SELECT 
           Enter your Message Here!!!
 INTO dummy 
        FROM mytable
      WHERE mytable.id=new.id
END IF;
END;
answered Sep 27, 2019 by Omaiz
• 560 points

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