How to input optional arguments in python command line?

0 votes

Hi All,

I would like to know how do I make an option file as an argument on command prompt in python. 

At present I using : 

if len(sys.argv) == 3:
first_log = sys.argv[1]
second_log = sys.argv[2]
else:

print "enter the second argument"

It works well for the following command : 

python test.py file1 file2 

However I have another case where only file1 may be present so file1 is mandatory for this script to run however file2 is optionnal :

if len(sys.argv) == 2:
first_log = sys.argv[1]
second_log = sys.argv[2]

pthon test.py file1 

It gives the error : 

second_log = sys.argv[2]
IndexError: list index out of range 

How do I achieve this because if python test.py file1 file2 then I would process both files?

Jul 11, 2019 in Python by Madhu
647 views

1 answer to this question.

0 votes

Please use this code.

if len(sys.argv) == 2:
first_log = sys.argv[1]
second_log = sys.argv[2]
answered Jul 11, 2019 by Suri

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