Python error "IndentationError: expected an indented block"

0 votes

I am trying to execute the following python code:

def example(p,q):

a = p.find(" ")
b = q.find(" ")
str_p = p[0:a]
str_q = p[b+1:]

if str_p == str_q:
    result = True
else:
    result = False
return result

And I get the folloeing error:

IndentationError: expected an indented block
Jun 17 in Python by Rhea
1,176 views

1 answer to this question.

0 votes

Python requires its code to be indented and spaced properly. Never mix tabs and spaces. If you're using tabs stick to tabs and if you're using space stick to space.

Also in your code, change this part:

if str_p == str_q:
    result = True
else:
    result = False
return result

To

return str_p == str_q
answered Jun 17 by Varun

edited Jun 17

Related Questions In Python

+1 vote
1 answer

How to print an error in Python?

For Python 2.6 and later and Python ...READ MORE

answered Aug 23, 2018 in Python by Priyaj
• 56,920 points
248 views
0 votes
1 answer

How can I print an Error in Python?

For Python 2.6 and later and Python ...READ MORE

answered Oct 12, 2018 in Python by ariaholic
• 7,340 points
49 views
0 votes
1 answer
+1 vote
2 answers

how can i count the items in a list?

Syntax :            list. count(value) Code: colors = ['red', 'green', ...READ MORE

answered Jul 6 in Python by Neha
• 330 points

edited Jul 8 by Kalgi 334 views
+4 votes
6 answers
0 votes
1 answer

Python error "TypeError: range() integer end argument expected, got numpy.float64."

Hi @Kashish, try something like this: for i ...READ MORE

answered May 27 in Python by Harish
141 views
0 votes
1 answer