Python Pandas ValueError DataFrame constructor not properly called

0 votes

I am trying to create a Python Pandas Dataframe using this code:


But I am getting this error:

ValueError: DataFrame constructor not properly called!
Mar 28, 2019 in Python by Shri

3 answers to this question.

+1 vote

The syntax is not right. The right syntax is as follows:

answered Mar 28, 2019 by Ritu
0 votes

You are providing a string representation of a dict to the DataFrame constructor, and not a dict itself. So this is the reason you get that error.

So if you want to use your code, you could do:

df = DataFrame(eval(data))

But better would be to not create the string in the first place, but directly putting it in a dict. Something roughly like:

data = []
for row in result_set:
    data.append({'value': row["tag_expression"], 'key': row["tag_name"]})

But probably even this is not needed, as depending on what is exactly in your result_set you could probably:

  • provide this directly to a DataFrame: DataFrame(result_set)
  • or use the pandas read_sql_query function to do this for you.
answered Dec 11, 2020 by Gitika
• 65,870 points
0 votes

It seems you need list:

df2 = pd.DataFrame(['Test'])
print (df2)
0  Test


It seems you need:

def multiple_dfs(file_name, sheet, *args):
    Put multiple dataframes into one xlsx sheet

    writer = pd.ExcelWriter(file_name)

    df = pd.DataFrame({'user': ['Bob', 'Jane', 'Alice'], 
               'income': [40000, 50000, 42000]})
    df2 = pd.DataFrame({'amount': [100, 500, 1000], 
               'income': [40000, 50000, 42000]})
    df3 = pd.DataFrame(['Title'])

    df.to_excel(writer, sheet, startrow=row, index=False)
    row += len(df) + 1
    df2.to_excel(writer, sheet, startrow=row, index=False)
    df3.to_excel(writer, sheet, startrow=0, startcol=0, header=None, \

answered Dec 11, 2020 by Rajiv
• 8,880 points

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