How do I use urllib to see if a website is 404 or 200 in Python

0 votes

How to get the code of the headers through urllib? Would appreciate some help with regard to this.

Nov 29, 2018 in Python by Anirudh
• 2,080 points

edited Dec 11, 2018 by Anirudh 13,286 views

1 answer to this question.

0 votes

For Python 3, try doing this:

import urllib.request, urllib.error

url = 'http://www.google.com/qqqq'
try:
    conn = urllib.request.urlopen(url)
except urllib.error.HTTPError as e:
    # Return code error (e.g. 404, 501, ...)
    # ...
    print('HTTPError: {}'.format(e.code))
except urllib.error.URLError as e:
    # Not an HTTP-specific error (e.g. connection refused)
    # ...
    print('URLError: {}'.format(e.reason))
else:
    # 200
    # ...
    print('good')
answered Nov 29, 2018 by Nymeria
• 3,560 points

edited Dec 11, 2018 by Nymeria
Good easy to understand solution, thanks!

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