How do I use urllib to see if a website is 404 or 200 in Python

Question

How to get the code of the headers through urllib? Would appreciate some help with regard to this.

Answer 1

For Python 3, try doing this:

import urllib.request, urllib.error

url = 'http://www.google.com/qqqq'
try:
    conn = urllib.request.urlopen(url)
except urllib.error.HTTPError as e:
    # Return code error (e.g. 404, 501, ...)
    # ...
    print('HTTPError: {}'.format(e.code))
except urllib.error.URLError as e:
    # Not an HTTP-specific error (e.g. connection refused)
    # ...
    print('URLError: {}'.format(e.reason))
else:
    # 200
    # ...
    print('good')

Comments

Good easy to understand solution, thanks!