How to upload to S3 bucket taking a photo with the iOS Camera

0 votes

I am trying to use the AWS S3 bucket to store user photos from when they have taken them from their phones. I right now have my code set up to the point where the user is able to take a photo of something and have that show up on the UIImageView.

The issue I am encountering is that I have no clue how to store it on the S3 bucket, I have code right now that is able to store a specified photo the bucket, but not really code that is able to store a photo that is taken from the camera.

Take Photo code

    @IBAction func takePhoto(_ sender: Any) {
        if UIImagePickerController.isSourceTypeAvailable(UIImagePickerController.SourceType.camera) {
            let imagePicker = UIImagePickerController()
            imagePicker.delegate = self
            imagePicker.sourceType = UIImagePickerController.SourceType.camera
            imagePicker.allowsEditing = false
            self.present(imagePicker, animated: true, completion: nil)

        }

    }
    func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [UIImagePickerController.InfoKey : Any]) {
        if let pickedImage = info[UIImagePickerController.InfoKey.originalImage] as? UIImage {
            takenPhoto.contentMode = .scaleToFill
            takenPhoto.image = pickedImage
            print(takenPhoto.image = pickedImage)
        }
        picker.dismiss(animated: true, completion: nil)



    }

AWS S3 Bucket Code

    @IBAction func uploadFile(_ sender: Any) {
        uploadFile(with: "eartj", type: ".jpeg")

    }


    func uploadFile(with resource: String, type: String){
        let key = "\(resource),\(type)"
        let imagePath = Bundle.main.path(forResource: resource, ofType: type)!
        let imageUrl = URL(fileURLWithPath: imagePath)

        let request = AWSS3TransferManagerUploadRequest()!

        request.bucket = "wuuurktest"
        request.key = key
        request.body = imageUrl
        request.acl = .publicReadWrite

        let transferManager = AWSS3TransferManager.default()

        transferManager.upload(request).continueWith(executor: AWSExecutor.mainThread()) { (task) -> Any? in
            if let error = task.error {
                print(error)

            }

            if task.result != nil {
                print("Uploaded File")

            }

            return nil

        }

    }


 

Nov 30, 2022 in Mobile Development by gaurav
• 22,940 points
48 views

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