How to avoid multiple nested for-loops when one nested for-loop has range up to the current iteration of the outer for-loop? For example, consider the following code: This program returns a triplet from a list arr such that arr[i] - arr[j] = arr[j] - arr[k] = d and i<j<k.

```d =3
arr = [1, 2, 4, 5, 7, 8, 10]
list1 = []

for biggest in range(0, len(arr)):
for bigger in range(0, biggest):
for big in range(0, bigger):
if abs(arr[big] - arr[bigger]) == d and abs(arr[bigger] - arr[biggest]) == d:
list1.append([arr[big], arr[bigger], arr[biggest]])
print(list1))```

Are there any other alternatives to using multiple nested loops? Sep 14, 2018 in Python 2,358 views

## 2 answers to this question.

+1 vote

You can replace the three loops with:

```from itertools import combinations

for big, bigger, biggest in combinations(range(0, len(arr)), 3):```

You can replace all the code with:

```print([t for t in combinations(arr, 3)
if t - t == t - t == d])``` answered Sep 14, 2018 by
• 57,530 points
+1 vote
Instead of multi-loop, If you can categorize all the threads into a loop, you can easily go with the less complexity with the in python, and for the nested loop, it is total standing with the loop in between the loop. answered Sep 15, 2018 by
• 160 points

edited Sep 15, 2018 by Vardhan

## Python: nested 'for' loops

Could use itertools: >>> for comb in itertools.combinations_with_replacement(range(9, -1, ...READ MORE

## How can I deal with python eggs for multiple platforms in one location?

Try virtualenv : http://pypi.python.org/pypi/virtualenv This helps you create isolated ...READ MORE

+1 vote

## instead of using two for loops in python

This example might help: for x, y in ((a,b) ...READ MORE

## how do i change string to a list?

suppose you have a string with a ...READ MORE

+1 vote

## how can i count the items in a list?

Syntax :            list. count(value) Code: colors = ['red', 'green', ...READ MORE

## how do i use the enumerate function inside a list?

can you give an example using a ...READ MORE