What is the point of function pointers

The purpose of function pointers is difficult for me to understand.

I suppose that would be helpful in certain situations—they do exist, after all—but I can't think of any circumstances in which using a function pointer is preferable or inevitable.

Could you provide some C or C++ examples of effective function pointer use?

Aug 17, 2022 in C++ by Nicholas
• 7,760 points • 401 views

No answer to this question. Be the first to respond.

Your answer

Your name to display (optional):

Email me at this address if my answer is selected or commented on:

Privacy: Your email address will only be used for sending these notifications.

What is the C++ function to raise a number to a power?

What's the best way to raise a n ...READ MORE

Jun 1, 2022 in C++ by Nicholas
• 7,760 points • 545 views

0 votes

1 answer

What is the name of the "<<" and ">>" operators? [duplicate]

According to cplusplus.com's documentation: This operator (<<) applied to ...READ MORE

answered Jun 20, 2022 in C++ by Damon
• 4,960 points • 401 views

0 votes

0 answers

What is the meaning of "generic programming" in c++?

What does generic programming in C++ mean? I'm ...READ MORE

Jul 11, 2022 in C++ by Nicholas
• 7,760 points • 637 views

0 votes

0 answers

What is the difference between cout, cerr, clog of iostream header in c++? When to use which one?

I looked up the differences between cout, ...READ MORE

Jul 27, 2022 in C++ by Nicholas
• 7,760 points • 736 views

0 votes

0 answers

What is meant with "const" at end of function declaration?

I received a book in which it is written: class Foo { public: int ...READ MORE

Jul 28, 2022 in C++ by Nicholas
• 7,760 points • 474 views

0 votes

1 answer

What is the best way to use a HashMap in C++?

The ordered and unordered map containers (std::map and std::unordered map) are included in the standard library. The items in an ordered map are sorted by key, and insert and access are in O (log n). For ordered maps, the standard library often use red black trees. However, this is only an implementation detail. Insert and access are in O in an unordered map (1). It is simply another term for a hashtable. An illustration using (ordered) std::map: #include <map> #include <iostream> #include <cassert> int main(int argc, char ...READ MORE

answered Jun 10, 2022 in C++ by Damon
• 4,960 points • 864 views

0 votes

1 answer

What is a smart pointer and when should I use one?

A smart pointer is similar to a ...READ MORE

answered Jun 2, 2022 in C++ by Damon
• 4,960 points • 492 views

0 votes

1 answer

Explanation of function pointers

It's a little perplexing. Function type and pointer to function type are distinct kinds (no more similar than int and pointer to int). However, in virtually all cases, a function type decays to a reference to a function type. In this context, rotting roughly refers to conversion (there is a difference between type conversion and decaying, but you are probably not interested in it right now). What matters is that practically every time you use a function type, you end up with a reference to the function type. But take note of the nearly - almost every time is not always! And there are rare circumstances where it does not. typedef void(functionPtr)(int); functionPtr fun = function; This code tries to clone one function to another (not the pointer! the function!) However, this is not feasible since functions in C++ cannot be copied. The compiler does not let this, and I'm surprised you got it compiled (you say you got linker errors?) Now for the code: typedef void(functionPtr)(int); functionPtr function; function(5); function does ...READ MORE

answered Jun 21, 2022 in C++ by Damon
• 4,960 points • 492 views

0 votes

0 answers

What are the differences between a pointer variable and a reference variable?

What distinguishes a reference variable from a ...READ MORE

Jul 11, 2022 in C++ by Nicholas
• 7,760 points • 450 views

0 votes

1 answer

What is this weird colon-member (" : ") syntax in the constructor?

Foo(int num): bar(num) In C++, this is known as a Member Initializer List. Simply put, it sets the value of your member bar to num. There is a significant difference between initializing a member with the Member initializer list and assigning a value to it within the function Object() { [native code] } body. When you use the Member initializer list to initialise fields, the constructors are only called once, and the object is constructed and initialised in a single operation. If you use assignment, the fields will be initialised with default constructors and then reassigned with actual values (via the assignment operator). As you can see, there is an extra overhead of creation and assignment in the latter, which may be significant for user defined classes. Cost of Member Initialization =Object ...READ MORE