What is this weird colon-member syntax in the constructor

0 votes
#include <iostream>

class Foo {
public:
  int bar;
  Foo(int num): bar(num) {};
};

int main(void) {
  std::cout << Foo(42).bar << std::endl;
  return 0;
}

What does this weird phrase mean: bar(num)? It appears to initialize the member variable, but this is the first time I've seen this syntax. It appears to be a call to a function/constructor, but for an int? It doesn't make sense to me. Someone might be able to shed some light on this for me. Are there any more arcane language features like this that you won't discover in a standard C++ book?

May 27, 2022 in Others by Nicholas
• 7,760 points
1,555 views

1 answer to this question.

0 votes

Foo(int num): bar(num)

In C++, this is known as a Member Initializer List.

Simply put, it sets the value of your member bar to num.

There is a significant difference between initializing a member with the Member initializer list and assigning a value to it within the function Object() { [native code] } body.

When you use the Member initializer list to initialise fields, the constructors are only called once, and the object is constructed and initialised in a single operation.

If you use assignment, the fields will be initialised with default constructors and then reassigned with actual values (via the assignment operator).

As you can see, there is an extra overhead of creation and assignment in the latter, which may be significant for user defined classes.

Cost of Member Initialization =Object Construction

 Cost of Member Assignment =Object Construction + Assignment
answered May 27, 2022 by Damon
• 4,960 points

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