Difference between struct and typedef struct in C

In C++, is there any difference between:

struct Foo { ... };

and:

typedef struct { ... } Foo;

Aug 8, 2022 in C++ by Nicholas
• 7,760 points • 729 views

No answer to this question. Be the first to respond.

Your answer

Your name to display (optional):

Email me at this address if my answer is selected or commented on:

Privacy: Your email address will only be used for sending these notifications.

What is the difference between public, private, and protected inheritance in C++?

To begin answering that question, let me characterise member accessors in my own terms. If you already know this, proceed to the section "next:". I'm aware of three types of accessors: public, protected, and private. Let: class Base { public: ...READ MORE

answered Jul 11, 2022 in C++ by Damon
• 4,960 points • 760 views

0 votes

0 answers

Difference between for loop and the range based loop in C++

The distinction between a for loop and ...READ MORE

Jul 11, 2022 in C++ by Nicholas
• 7,760 points • 600 views

0 votes

1 answer

What is the difference between operator overloading and operator overriding in C++?

Some people use the latter word to ...READ MORE

answered Aug 2, 2022 in C++ by Damon
• 4,960 points • 1,947 views

0 votes

0 answers

What is the difference between std::list<std::pair> and std::map in C++ STL?

What distinguishes std::list<std::pair> from std::map? Does the ...READ MORE

Aug 17, 2022 in C++ by Nicholas
• 7,760 points • 659 views

0 votes

1 answer

C++ code file extension? What is the difference between .cc and .cpp [closed]

GNU GCC recognizes all of the following ...READ MORE

answered Jun 21, 2022 in C++ by Damon
• 4,960 points • 1,531 views

0 votes

1 answer

Difference between Turbo C++ and Borland C++ compiler [closed]

I will try my best to respond, ...READ MORE

answered Jun 21, 2022 in C++ by Damon
• 4,960 points • 1,182 views

0 votes

1 answer

Explanation of function pointers

It's a little perplexing. Function type and pointer to function type are distinct kinds (no more similar than int and pointer to int). However, in virtually all cases, a function type decays to a reference to a function type. In this context, rotting roughly refers to conversion (there is a difference between type conversion and decaying, but you are probably not interested in it right now). What matters is that practically every time you use a function type, you end up with a reference to the function type. But take note of the nearly - almost every time is not always! And there are rare circumstances where it does not. typedef void(functionPtr)(int); functionPtr fun = function; This code tries to clone one function to another (not the pointer! the function!) However, this is not feasible since functions in C++ cannot be copied. The compiler does not let this, and I'm surprised you got it compiled (you say you got linker errors?) Now for the code: typedef void(functionPtr)(int); functionPtr function; function(5); function does ...READ MORE