Data frames and is nan

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Sum(is.na(my.df)) worked as predicted when I used it to determine whether my data frame contained any NAs, but sum(is.nan(my.df)) did not.

My.df - data.frame (a=c(1, 2, 3), b=c(5, NA, NaN)) a. my.df b
1 1 5 2 2 NA\s3 3 NaN\s> (my.df) is.na a b
[1,] TRUE TRUE [2,] TRUE FALSE [3,] TRUE FALSE > a b is.nan(my.df)
sum(is.na(my.df)) = FALSE FALSE
Sum(is.nan(my.df)) = [1] 2
[1] 0
I'm sorry. Is there a justification for the inconsistent actions? Is it a result of poor implementation, or is it deliberate? What does is.nan(my.dfreturn )'s value mean? Is there a solid reason why an entire data frame shouldn't be used with is.nan()?

The parameter types appear to be the same in the documentation for is.na() and is.nan().
Jul 20, 2022 in Data Science by avinash
• 1,840 points
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