How to convert string to char array in C

0 votes

I want to convert a string to a char array, not a char*. I know how to convert a string to a char* (using malloc or the method I described in my code), but that's not what I'm looking for. I'm only looking for a way to convert a string to a char[size] array. Is that even possible?

#include <iostream>
#include <string>
#include <stdio.h>
using namespace std;

int main()
{
    // char to string
    char tab[4];
    tab[0] = 'c';
    tab[1] = 'a';
    tab[2] = 't';
    tab[3] = '\0';
    string tmp(tab);
    cout << tmp << "\n";

    // string to char* - but thats not what I want

    char *c = const_cast<char*>(tmp.c_str());
    cout << c << "\n";

    //string to char
    char tab2[1024];
    // ?

    return 0;
}

Jun 15 in C++ by Nicholas
• 2,460 points
6 views

1 answer to this question.

0 votes

Simplest way I can think of doing it is:

string temp = "cat";
char tab2[1024];
strcpy(tab2, temp.c_str());

For safety, you might prefer:

string temp = "cat";
char tab2[1024];
strncpy(tab2, temp.c_str(), sizeof(tab2));
tab2[sizeof(tab2) - 1] = 0;

or could be in this fashion:

string temp = "cat";
char * tab2 = new char [temp.length()+1];
strcpy (tab2, temp.c_str());
answered Jun 20 by Damon
• 3,580 points

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