Difference between del remove and pop on lists

Question

>>> a=[1,2,3] 

>>> a.remove(2) 

>>> a [1, 3]

>>> a=[1,2,3] 

>>> del a[1] 

>>> a [1, 3] 

>>> a= [1,2,3] 

>>> a.pop(1) 2 

>>> a [1, 3] 

>>>

Is there any difference between the above three methods to remove an element from a list?

Answer 1

es, remove removes the first matching value, not a specific index:

>>> a = [0, 2, 3, 2] 

>>> a.remove(2) 

>>> a [0, 3, 2]

del removes the item at a specific index:

>>> a = [3, 2, 2, 1] 

>>> del a[1] [3, 2, 1]

and pop removes the item at a specific index and returns it.

>>> a = [4, 3, 5] 

>>> a.pop(1) 3 

>>> a [4, 5]

Their error modes are different too:

>>> a = [4, 5, 6]

>>> a.remove(7)

Traceback (most recent call last):

File "<stdin>", line 1, in <module>

ValueError: list.remove(x): x not in list

>>> del a[7]

Traceback (most recent call last):

File "<stdin>", line 1, in <module>

IndexError:

list assignment index out of range

>>> a.pop(7)

Traceback (most recent call last):

File "<stdin>", line 1, in <module>

IndexError: pop index out of range