196178/how-can-i-get-the-size-of-a-c-function
In C++, how can I find the size of a function?
Assume I have a function:
void f() { /*do something*/ }
... By "size of f," I mean the length of the code that will /*do something*/ beginning at the location specified by a reference to f.
This method worked for me. for( multimap<char,int>::iterator it ...READ MORE
In C++, how can I find the greatest or minimum value in a vector? Is it correct to assume that it would be similar with an array? Do I require an iterator? I tried max element, but I kept receiving errors. vector<int>::const_iterator it; it = max_element(cloud.begin(), cloud.end()); error: request for ...READ MORE
It is part of a series. Replace pow() with the previous iteration's value. There is no need for code to call pow (). Pow(x, 5 * I - 1) and pow(-1, I - 1) may be formed since both have an int exponent dependent on the iterator I from the previous loop iteration. Example: Let f(x, i) = pow(x, 5 * i ...READ MORE
I used the printf() command to produce the output seen below: printf("She said time flies like an arrow, ...READ MORE
There are some new convert methods in C++ that convert std::string to a numeric type. As an alternative to str.c str() atoi(str.c str()) atoi(str.c str() you can make use of std::stoi std::stoi ...READ MORE
What's the best way to raise a n ...READ MORE
It's a little perplexing. Function type and pointer to function type are distinct kinds (no more similar than int and pointer to int). However, in virtually all cases, a function type decays to a reference to a function type. In this context, rotting roughly refers to conversion (there is a difference between type conversion and decaying, but you are probably not interested in it right now). What matters is that practically every time you use a function type, you end up with a reference to the function type. But take note of the nearly - almost every time is not always! And there are rare circumstances where it does not. typedef void(functionPtr)(int); functionPtr fun = function; This code tries to clone one function to another (not the pointer! the function!) However, this is not feasible since functions in C++ cannot be copied. The compiler does not let this, and I'm surprised you got it compiled (you say you got linker errors?) Now for the code: typedef void(functionPtr)(int); functionPtr function; function(5); function does ...READ MORE
You're mostly correct regarding cout and cin. ...READ MORE
Using function pointers as arguments for other ...READ MORE
Hello, let's say I have an abstract class with a few pure abstract functions and a few classes that derive from it, and all of the data from these classes eventually becomes similar, I was wondering if it would be wise, or even possible, to declare a vector under protected in the abstract class to collect the data so something like that. class A { protected: vector <string> ...READ MORE
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