how to print array integer without bracket in python like result 1 2 3 4 5

+3 votes
Aug 4, 2018 in Python by Abhishek
• 240 points
8,110 views

2 answers to this question.

+1 vote
Best answer

Hey @abhijmr.143, you can print array integers in the format mentioned in your question with the following code:

Code:

from __future__ import print_function 
a = [1,2,3,4,5]
for value in a: 
    print(value, end=',') 
print("\b",end="") 
print(" ") 

Output:

1,2,3,4,5

Explanation:

from __future__ import print_function #This line is only needed in Python 2.X, you can skip this line if you are using python 3.X
a = [1,2,3,4,5] #array initialization
for value in a: #loop to print all array elements
    print(value, end=',') #This line prints the array integers with a comma(,) as its suffix and prints a comma even after the last integer
print("\b",end="") #This line is used to move the cursor to the last printed character
print(" ") #This line replaces the comma(,) printed after the last integer with a blank space
answered Aug 5, 2018 by Omkar
• 69,220 points

edited Aug 8, 2018 by Omkar
+1 vote

from __future__ import print_function

data = [7, 7, 7, 7]
print(*data, sep='')
answered Aug 6, 2018 by Sushmita
• 6,920 points
This code will print the output as follows:
7777

To print the data as mentioned in the question, edit the last line of your code as follows:
print(*data, sep=',')

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