TypeError float object cannot be interpreted as an integer

0 votes

Hi Guys,

I am trying to use the range function in my code. But it is showing me the below error.

TypeError                                 Traceback (most recent call last)
<ipython-input-13-a83306d87fcd> in <module>
      1 # floats with python range
----> 2 for i in range(0.1, 0.5, 0.1):
      3     print(i)
TypeError: 'float' object cannot be interpreted as an integer

How can I solve this error?

Jun 29, 2020 in Python by akhtar
• 38,230 points

2 answers to this question.

+1 vote


The range function does not work with floats. Only integer values can be specified as the start, stop, and step arguments. But you can use this in a different way. I have attached one example for your reference.

def range_with_floats(start, stop, step):
    while stop > start:
        yield start
        start += step
for i in range_with_floats(0.1, 0.5, 0.1):

I hope this will help you.

answered Jun 29, 2020 by MD
• 95,440 points
0 votes

Python has two data types that represent numbers: floats and integers. These data types have distinct properties.

If you try to use a float with a function that only supports integers, like the range() function, you’ll encounter the “TypeError: ‘float’ object cannot be interpreted as an integer” error.

TypeError: ‘float’ object cannot be interpreted as an integer

Floating-point numbers are values that can contain a decimal point. Integers are whole numbers. It is common in programming for these two data types to be distinct.

In Python programming, some functions like range() can only interpret integer values. This is because they are not trained to automatically convert floating-point values to an integer.

This error is commonly raised when you use range() with a floating-point number to create a list of numbers in a given range.

answered Dec 16, 2020 by Gitika
• 65,910 points

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