Python urllib2 Response header

0 votes

I'm trying to extract the response header of a URL request. When I use firebug to analyze the response output of a URL request, it returns:

Content-Type text/html

However when I use the python code:

urllib2.urlopen(URL).info()

the resulting output returns:

Content-Type: video/x-flv

I am new to python, and to web programming in general; any helpful insight is much appreciated. Also, if more info is needed please let me know.

Thanks in advance!

Jun 28, 2019 in Python by ana1504.k
• 7,910 points
2,058 views

1 answer to this question.

0 votes

Try to request as Firefox does. You can see the request headers in Firebug, so add them to your request object:

import urllib2

request = urllib2.Request('http://your.tld/...')
request.add_header('User-Agent', 'some fake agent string')
request.add_header('Referer', 'fake referrer')
...
response = urllib2.urlopen(request)
# check content type:
print response.info().getheader('Content-Type')
answered Jun 28, 2019 by SDeb
• 13,300 points

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