Reconstruct an array by replacing every element with a i-1 K - Python

0 votes
I've recently started learning python and I've got an assignment to complete. One of the questions was to reconstruct an array by replacing every element with a[[i-1]%K]. Can somebody help me with this? Thanks you
Jun 14, 2019 in Python by Varsha

edited Jun 17, 2019 by Kalgi 482 views

1 answer to this question.

0 votes

Hey varsha, Have a look at this one:

def construct(s, k, a):
    index = 0
    # Finding the index which is not -1
    for i in range(s):
        if (a[i]!=-1):
            index = i
            break
    # Calculating the values of the indexes index-1 to 0
    for i in range(index-1, -1, -1):
        if (a[i]==-1):
            a[i]=(a[i + 1]-1 + k)% k
    # Calculating the values of the indexes index + 1 to n
    for i in range(index + 1, s):
        if(a[i]==-1):
            a[i]=(a[i-1]+1)% k
            print(a)
# Driver code
s, k = 6, 7
a =[1, 2, 3, 4, 5, 6]
construct(s, k, a)

It should give you the following output:

answered Jun 14, 2019 by Miya

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