A value which should be judged by a scale gets bad judgement sometimes

0 votes

A weight measurement exists and provides us with various numbers. However, there is always a reference weight, such as 100, thus the Min-Max will always be within 10%. (90 - 110).

It is the responsibility of the code to determine whether anything is acceptable or not. For example, if it is 89.9, that is NOT GOOD, but if it is 99.2, that is OK.

Sometimes a problem arises for no apparent reason because, despite being on the scale, it goes BAD, and other times it is not on the scale and goes OK.

This is the section of the code that is crucial; (Not mine code, I just have to fix it somehow)

                    If Val(txtWeight.Value) < Val(txtMinWeight.Value) Or Val(txtWeight.Value) > Val(txtMaxWeight.Value) Then
                        lblJudgement.Caption = "NOT GOOD"
                        Sheets("Measurment").Cells(j, 2).Value = "NOT GOOD"
                        lblJudgement.BackColor = 255
                        txtWeight.BackColor = 255
                        Call BadSound
                    Else
                        lblJudgement.Caption = "OK"
                        Sheets("Measurment").Cells(j, 2).Value = "OK"
                        lblJudgement.BackColor = 49152
                        txtWeight.BackColor = 49152
                        Call GoodSound
                    End If

As long as I see it, all the formulas, and calculations should be good, so I have no clue why it turns around sometimes and give back wrong judgments.

Jan 8, 2023 in Others by Kithuzzz
• 38,010 points
300 views

1 answer to this question.

0 votes
Only the period (.) is accepted by the Val function as a legitimate decimal separator. Use CDbl to convert a string to a number instead when various decimal separators are employed, such as in foreign applications.
answered Jan 8, 2023 by narikkadan
• 63,720 points

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