how the iterator in c could be printed

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Suppose, I have declared a vector in C++ like this:

vector<int>numbers = {4,5,3,2,5,42};

I can iterate it through the following code:

for (vector<int>::iterator it = numbers.begin(); it!=numbers.end(); it++){
    // code goes here
}

I'd now want to discuss programming in the for loop block.

I can use this iterator to access and modify any value. 

Let's imagine that I want to tenfold the print and every value. 

The code would then be:

*it+=10;
cout << *it << endl;

I have the ability to output the addresses of both the iterator and the elements being iterated.

You may output the iterator's address by using:

cout << &it << endl;

Address of iterated elements can be printed by:

cout << &(*it) << endl;

But why the iterator itself could not printed by doing the following?

cout << it <<endl;

I initially believed the convention was a JAVA invention due to its security-related nature. 

If it is, though, how come I was able to print its address?

But is there another way to accomplish this? 

Why not, then?

Jul 11, 2022 in C++ by Nicholas
• 7,760 points
635 views

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