Compare 1 with another string in bash

Question

I've spent 2 hours with an if statement, that never works like I want:

#should return true
if [ "$1" == "355258054414904" ]; then 

Here is the whole script:

#!/bin/bash

param=$1
INPUT=simu_900_imei_user_pass.csv
OLDIFS=$IFS
IFS=,
[ ! -f $INPUT ] && { echo "$INPUT ime not found"; exit 99; }
while read imei email pass 
do
    echo "First Parameter-IMEI: $1"
    if [ "$1" == "355258054414904" ]; then
        echo "GOOD"
    fi
done < $INPUT
IFS=$OLDIFS

This is the output of the script:

First Parameter-IMEI: 355258054414904
First Parameter-IMEI: 355258054414904
First Parameter-IMEI: 355258054414904

I have seen a lot of pages about the subject, but I can't make it work :(

EDIT: I Join the content of csv for better understanding ! Tx for your help !

4790057be1803096,user1,pass1
355258054414904,juju,capp
4790057be1803096,user2,pass2
358854053154579,user3,pass3