Understanding the probability of a double-six if i roll two dice

Question

The probability of a double-six in one throw of two die is 1/36 or 0.028.

If I threw a pair of die a hundred times would 3 (0.028 * 100) be

1. The amount of times (3) I would get a double-six

OR

1. The probability (3%) of getting a double-six on all throws.

I have a feeling the correct answer is number 1, because intuitively the chance of getting a double six every time on a hundred throws seems to be a lot lower than 3%.

Please explain, as simply as you can, which is the correct understanding and why?

Answer 1

The chance of not getting a double six in a single throw (all but one outcome divided by all outcomes):

35/36

The chances of not getting a double six in k throws

(35/36)**k /* where ** is raised to the k-th power */

The likelihood of at least one double six being thrown in k throws

P(k) = 1 - (35/36)**k

if k ==100 We've got

 P(100) == 0.94022021

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