How can I solve this example in an easy way

Question

Write a program that lets the user to enter any two integers and weave them digit by digit and print the result of weaving their digits together to form a single number. Two numbers x and y are weaved together as follows. The last pair of digits in the result should be the last digit of x followed by the last digit of y. The second-to-the-last pair of digits in the result should be the second-to the-last digit of x followed by the second-to-the-last digit of y. And so on.

Answer 1

You can use this code:

import java.util.*;

public class sample{

public static void main(String args[])

{

System.out.println("Enter value of X");

Scanner in = new Scanner(System.in);

String x = in. nextLine();

int x_int = Integer.parseInt(x);

int length_x = String.valueOf(x).length();

System.out.println("Enter value of Y");

String y = in. nextLine();

int y_int = Integer.parseInt(y);

int length_y = String.valueOf(y).length();

int result=0;

int temp;

int min;

if(y_int>x_int) {

min=length_x;

}

else {

min=length_y;

}


for(int i=1;i<=min;i++)

{

int dig = String.valueOf(result).length();

temp=y_int%10;

for (int j=0;j<dig;j++)

{

temp=temp*10;

}

result = result+temp;

y_int=y_int/10;

dig = String.valueOf(result).length();

temp=x_int%10;

for (int j=0;j<dig;j++)

{

temp=temp*10;

}

result = result+temp;

x_int=x_int/10;



}

if(y_int>x_int) {

for(int i=1;i<=length_y-min;i++)

{

int dig = String.valueOf(result).length();

temp=y_int%10;

for (int j=0;j<dig;j++)

{

temp=temp*10;

}

result = result+temp;

y_int=y_int/10;

}

}

else if(y_int<x_int){

for(int i=1;i<=length_x-min;i++)

{

int dig;

dig = String.valueOf(result).length();

temp=x_int%10;

for (int j=0;j<dig;j++)

{

temp=temp*10;

}

result = result+temp;

x_int=x_int/10;

}

}

System.out.println("Result = "+result/10);

}

}