Python while sampling

0 votes

I'm searching to make a loop to go throw samples till I reach the result. Example:

    i=(list(np.random.randint(2, size=5)),list(np.random.randint(2,  size=2)),list(np.random.randint(2, size=7)),list(np.random.randint(2, size=7)),list(np.random.randint(2, size=9)),list(np.random.randint(2, size=8)),list(np.random.randint(2, size=7)))

    tot=0
    for j in range(0,len(anytable)):
        if resp(i,(anytable.iloc[j,0:7].tolist())):  #this function "resp"  gives me True and False and add 1 to variable "tot"
           tot=tot+1

Now I want to stop till I have to tot>=100 . So I have to generate many "i" samples lists till I get to tot>=100.

How can I do this?

Thank you very much

Sep 20, 2018 in Python by bug_seeker
• 15,520 points
323 views

1 answer to this question.

0 votes

I would say, this could be your solution.

j, tot = 1, 1
while j<len(anytable) and tot<100 :
    tot += int( resp(i,(anytable.iloc[j,0:7].tolist())) )
    j   += 1

The condition is false if one of the inequations is false. The incementing operator += on tot is adding the integer representation of a boolean True = 1 or False = 0 to the value of tot.

answered Sep 20, 2018 by Priyaj
• 58,090 points

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