How to enable Bootstrap tooltip on disabled button

0 votes

I need to display a tooltip on a disabled button and remove it on an enabled button. Currently, it works in reverse.

What is the best way to invert this behaviour?

$('[rel=tooltip]').tooltip();

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script>
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" rel="stylesheet"/>
<hr>
<button class="btn" disabled rel="tooltip" data-title="Dieser Link führt zu Google">button disabled</button>
<button class="btn" rel="tooltip" data-title="Dieser Link führt zu Google">button not disabled</button>
May 12, 2020 in JQuery by kartik
• 37,490 points
1,844 views

1 answer to this question.

0 votes

Hii @kartik,

You can wrap the disabled button and put the tooltip on the wrapper:

<div class="tooltip-wrapper" data-title="Dieser Link führt zu Google">
  <button class="btn btn-default" disabled>button disabled</button>
</div>

If the wrapper has display:inline then the tooltip doesn't seem to work. 

Using display:block and display:inline-block seem to work fine. It also appears to work fine with a floated wrapper.

Thank You!!

answered May 12, 2020 by Niroj
• 82,680 points

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