How come an array s address is equal to its value in C

0 votes

The pointer values and pointer addresses in the next section of code differ as anticipated.

Array values and addresses, however, do not!

How is this possible?

#include <stdio.h>
int main()
{
  char my_array[100] = "some cool string";
  printf("my_array = %p\n", my_array);
  printf("&my_array = %p\n", &my_array);

  char *pointer_to_array = my_array;
  printf("pointer_to_array = %p\n", pointer_to_array);
  printf("&pointer_to_array = %p\n", &pointer_to_array);

  printf("Press ENTER to continue...\n");
  getchar();
  return 0;
}

Output:

my_array = 0022FF00
&my_array = 0022FF00
pointer_to_array = 0022FF00
&pointer_to_array = 0022FEFC
Aug 8, 2022 in C++ by krishna
• 2,820 points
325 views

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