How to comment out HTML and PHP together

0 votes

I have this code,

    <tr>
      <td><?php echo $entry_keyword; ?></td>
      <td><input type="text" name="keyword" value="<?php echo $keyword; ?>" /></td>
    </tr>
    <tr>
      <td><?php echo $entry_sort_order; ?></td>
      <td><input name="sort_order" value="<?php echo $sort_order; ?>" size="1" /></td>
    </tr>

and I would love to comment both in one shot...but when I try

    <!-- <tr>
      <td><?php echo $entry_keyword; ?></td>
      <td><input type="text" name="keyword" value="<?php echo $keyword; ?>" /></td>
    </tr>
    <tr>
      <td><?php echo $entry_sort_order; ?></td>
      <td><input name="sort_order" value="<?php echo $sort_order; ?>" size="1" /></td>
    </tr> -->

the page fails - it seems the PHP code is not being commented out... Is there a way to do this?

Oct 6, 2020 in PHP by kartik
• 37,490 points
77 views

1 answer to this question.

0 votes

Hello @kartik,

Instead of using HTML comments (which have no effect on PHP code -- which will still be executed), you should use PHP comments:

<?php /*
<tr>
      <td><?php echo $entry_keyword; ?></td>
      <td><input type="text" name="keyword" value="<?php echo $keyword; ?>" /></td>
    </tr>
    <tr>
      <td><?php echo $entry_sort_order; ?></td>
      <td><input name="sort_order" value="<?php echo $sort_order; ?>" size="1" /></td>
    </tr>
*/ ?>


With that, the PHP code inside the HTML will not be executed; and nothing (not the HTML, not the PHP, not the result of its non-execution) will be displayed.

Hope it helps!!

Thank You!!

answered Oct 6, 2020 by Niroj
• 82,560 points

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