How do I call a Django function on button click

0 votes

I am trying to write a Django application and I am stuck at how I can call a view function when a button is clicked.

In my template, I have a link button as below, when clicked it takes you to a different webpage:

<a target="_blank" href="{{ column_3_item.link_for_item }}">Check It Out</a>

When the button is clicked, I also want to call a Django view function (along with re-direct to a target website). The view function increments the value in the database which stores the number of times the button is clicked.

What I would like to do is to call a Django view function also when the button is clicked which updates the database without refreshing the page. How I can achieve this?

Jun 23, 2020 in Python by kartik
• 37,520 points
60,807 views

1 answer to this question.

0 votes

Hello @kartik,

There are 2 possible solutions that I personally use

1.without using form

 <button type="submit" value={{excel_path}} onclick="location.href='{% url 'downloadexcel' %}'" name='mybtn2'>Download Excel file</button>

2.Using Form

<form action="{% url 'downloadexcel' %}" method="post">
{% csrf_token %}


 <button type="submit" name='mybtn2' value={{excel_path}}>Download results in Excel</button>
 </form>

Where urls.py should have this

path('excel/',views1.downloadexcel,name="downloadexcel"),

Hope this is helpful!

answered Jun 23, 2020 by Niroj
• 82,880 points

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