Destructure a function parameter in Typescript

0 votes

I'm trying to give a type to the members of below function. args is an object with a data property of type UserCreateInput

So, from this:

createUser(parent: any, args: any, context: any) {
    return context.prisma.createUser(args.data)
}

I wrote this:

createUser(parent: any, args: {data: UserCreateInput}, context: any) {
    return context.prisma.createUser(args.data)
}

I'm not sure how to replace 'xxx' in createUser(parent: any, xxx, context: any) so I can simply return return context.prisma.createUser(data)

Jun 8, 2022 in TypeSript by Logan
• 2,140 points
112 views

1 answer to this question.

0 votes

You can use the object de-structuring syntax:

createUser(parent: any, { data }: { data: UserCreateInput }, context: any) {
    return context.prisma.createUser(data)
}
answered Jun 9, 2022 by Nina
• 3,020 points

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