Reading Excel File using Python how do I get the values of a specific column with indicated column name

Question

How do I read the content of a specific column with provided name, given that the FORMAT is configurable?

This is what I tried. Currently I'm able to read all the content in the file

from xlrd import open_workbook
wb = open_workbook('sample.xls')
for s in wb.sheets():
    #print 'Sheet:',s.name
    values = []
    for row in range(s.nrows):
        col_value = []
        for col in range(s.ncols):
            value  = (s.cell(row,col).value)
            try : value = str(int(value))
            except : pass
            col_value.append(value)
        values.append(col_value)
print values

My output is :

[
    [u'Arm_id', u'DSPName', u'DSPCode', u'HubCode', u'PinCode', u'PPTL'],
    ['1', u'JaVAS', '1', u'AGR', '282001', u'1,2'], 
    ['2', u'JaVAS', '1', u'AGR', '282002', u'3,4'], 
    ['3', u'JaVAS', '1', u'AGR', '282003', u'5,6']
]

Then I loop around values[0] trying to find out the FORMAT content in values[0] and then getting the index of Arm_id, DSPname and Pincode in the values[0] and then from next loop I know the index of all the FORMAT factors , thereby getting to know which value do I need to get .

But this is such a poor solution.

How do I get the values of a specific column with name in excel file?

Answer 1

We can read excel more easily with pandas.

import pandas as pd 
from pandas import ExcelWriter
from pandas import ExcelFile 
DataF=pd.read excel("Test.xlsx",sheet name='Sheet1')
enlarge ("Column headings:")
print(DataF.columns)