How to post the parameter in ajax call of jquery datatable

0 votes

I am passing parameter along with URL in ajax call of data table.

But I want to pass it as POST method,  so anyone can help me regarding parameter passing in post method?

Here's my  code:

// Sending through GET
var $table = $('#example').dataTable( 
    "processing": true,
    "serverSide": true,
    "bDestroy": true,
    "bJQueryUI": true,
    "ajax": 'getResult.php?formName=afscpMcn&action=search&mcn_no='+mcnNum+'&cust_nm='+cust_num+'&emp_id='+emp+''
});
Jun 16, 2020 in PHP by kartik
• 37,510 points
12,044 views

1 answer to this question.

0 votes

Hello @kartik,

Just pass it like a normal jQuery ajax in POST fashion.

The structure should look like this:

ajax: { type: 'POST', url: <path>, data: { your desired data } }

Example:

var $table = $('#example').dataTable( 
    "processing": true,
    "serverSide": true,
    "bDestroy": true,
    "bJQueryUI": true,
    "ajax": {
        'type': 'POST',
        'url': 'getResult.php',
        'data': {
           formName: 'afscpMcn',
           action: 'search',
           // etc..
        },
    }
});

In PHP, just access the POST indices as usual (just the straightforward approach):

getResult.php

$form_name = $_POST['formName'];
// the rest of your values ...

Hope this is helpfull!!

Thank You!!

answered Jun 16, 2020 by Niroj
• 82,780 points

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