Understand How to Sort Dictionary by Value in Python

Python is a high-level programming language that has been designed in C. It follows the object-oriented programming approach. Sorting a dictionary in Python by value is one of the many things one can do and in this article, I will teach how to Sort Dictionary by Value in Python.

• Prerequisites: Sort Dictionary by Value in Python
• Problem Statement
• Approach
• Practical examples: Sort Dictionary by Value in Python

Prerequisites: Sort Dictionary by Value in Python

 In order to create a program in Python which can sort a dictionary by value, the following prerequisites must be met. 

• Dictionary: In Python dictionary can be defined as an unorganized collection of data that is used to store data values like maps, and other elements that hold a key-value pair. 
• List: A list is similar to arrays in Python; it might contain a collection of various data items such as strings, integers, floating numbers etc. 
• Merging Two Dictionaries: Merging two dictionaries is an internal function in Python that can be achieved quite easily. 
• Dictionary Methods: Dictionary methods is again a Python internal function that will be used in the context of this program.

Now that you know the various prerequisites that will be required, let’s get down on how to actually write this program. 

Problem Statement 

• Create a dictionary and arrange as well as display all its keys alphabetically. 
• Display the key-values as well as names alphabetically and display them. 

Approach 

In order to create a program that addresses the above-shared problem statement, we will make use of the following functions as well as modules. 

• Make use of the key_value.iterkeys()  function to sort all the keys alphabetically. 
• Use the sorted (key_value) to sort all the values alphabetically and print them onto the screen of the user. 
• Sort the final list of key values using the functions key_value.iteritems(), key = lambda (k, v) : (v, k)).

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Practical Examples: Sort Dictionary by Value in Python

Now that all the functions and modules to be used have been explained, let’s look at a couple of examples to understand their implementation better. 

Example #1

def dictionairy():
key_value ={}

key_value[2] = 56
key_value[1] = 2
key_value[5] = 12
key_value[4] = 24
key_value[6] = 18
key_value[3] = 323
print ("First Taskn")
print ("Keys are")
for i in sorted (key_value.keys()) :
      print(i, end = " ")
def main():
      dictionairy()
if __name__=="__main__":
      main()

//Output:

First Task
Keys are
1 2 3 4 5 6

Example #2

def dictionairy():
key_value ={}
key_value[2] = 56
key_value[1] = 2
key_value[5] = 12
key_value[4] = 24
key_value[6] = 18
key_value[3] = 323
print ("Task 2:-nKeys and Values sorted in", "alphabetical order by the key ")
for i in sorted (key_value) :
      print ((i, key_value[i]), end =" ")
def main():
      dictionairy()
if __name__=="__main__":
      main()

//Output:

Task 2: -
Keys and Values sorted in alphabetical order by the key  
(1, 2) (2, 56) (3, 323) (4, 24) (5, 12) (6, 18)

Example #3

def dictionairy():
key_value ={}
key_value[2] = 56
key_value[1] = 2
key_value[5] = 12
key_value[4] = 24
key_value[6] = 18
key_value[3] = 323
print ("Task 3:-nKeys and Values sorted", "in alphabetical order by the value")
print(sorted(key_value.items(), key = lambda kv:(kv[1], kv[0])))
def main():
       dictionairy()
if __name__=="__main__":
       main()

//Output:

Task 3:-
Keys and Values sorted in alphabetical order by the value
[(1, 2), (5, 12), (6, 18), (4, 24), (2, 56), (3, 323)]

Example #4

mydict = {"carl": 40, "alan": 2, "bob": 1, "danny": 3,}
for key in sorted(mydict.keys()):
       print("%s: %s" % (key, mydict[key]))

//Output:

alan: 2
bob: 1
carl: 40
danny: 3

Example #5

for key, value in sorted(mydict.items(), key=lambda item: item[1]):
    print("%s: %s" % (key, value))

The output for the above program will be,

bob: 1
alan: 2
danny: 3
carl: 40

Example #6

#!/usr/bin/env python
from __future__ import print_function
scores = {
   'Foo' : 10,
   'Bar' : 34,
   'Miu' : 88,
}
print(scores) # {'Miu': 88, 'Foo': 10, 'Bar': 34}
sorted_names = sorted(scores)
print(sorted_names)  # ['Bar', 'Foo', 'Miu']
for s in sorted_names:
    print("{}  {}".format(s, scores[s]))
print(sorted(scores.values())) # [10, 34, 88]
print('')
sorted_names = sorted(scores, key=lambda x: scores[x])
for k in sorted_names:
    print("{} : {}".format(k, scores[k]))
print('')
sorted_names = sorted(scores, key=scores.__getitem__)
for k in sorted_names:
    print("{} : {}".format(k, scores[k]))

With this, we come to an end of this article I hope you have understood how to sort a Dictionary in Python through some real-time examples.

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