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Java Program to find the Largest Number in an Array
In this tutorial, I am going to help you to build a Java code through which you can find out the largest number in an array. After you enter the numbers of the array as an input, the program will start comparing the numbers with each other and reach its conclusion.
The pointers to be discussed are as follows:
It’s simple. You need to declare an array at the begging of the program. The program would scan the code using the for loop and would conclude its result(the largest number) from the array that has been declared initially. Refer the coed snippet below:
arr[]= {5, 45,20,80,4,160,90,86}
Output: 160
Code:
public class Example { public static void main(String[] args) { int n, max; Scanner s = new Scanner(System.in); System.out.print("Enter the number of elements in the array:"); n = s.nextInt(); int a[] = new int[n]; System.out.println("Enter the elements of array:"); for(int i = 0; i < n; i++) { a[i] = s.nextInt(); } max = a[0]; for(int i = 0; i < n; i++) { if(max < a[i]) { max = a[i]; } } System.out.println("Maximum value in the array is:"+max); } }
Output:
Enter the number of elements in the array:5
Enter the elements of array:
10
4
8
1
3
Maximum value in the array is: 10
Code 2
Moving on with a simpler approach.
class LargestNumber { public static void main(String args[]) { int[] a = new int[] { 22, 3, 550, 4, 11, 100}; int max = a[0]; for(int i = 1; i < a.length;i++) { if(a[i] > max) { max = a[i]; } } System.out.println("The Given Array is:"); for(int i = 0; i < a.length;i++) { System.out.println(a[i]); } System.out.println("The Largest Number is:" + max); } }
Output:
The given array is:
22
3
550
4
11
100
The largest number is: 550
In this example, we have used for loop to reach to our aim. I hope you have understood the usage by now!
This is how we can accomplish our goal through Java code. I hope you are clear with the concept. Keep reading, keep exploring!
If you’re just beginning, then watch at this Java Tutorial to Understand the Fundamental Java Concepts.
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